CoDEVIANT #10 (4/2/19)

Description:

Encrypt this!

  1. Your message is a string containing space separated words.
  2. You need to encrypt each word in the message using the following rules:
  • The first letter needs to be converted to its ASCII code.
  • The second letter needs to be switched with the last letter
  1. Keepin’ it simple: There are no special characters in input.

Examples:

encryptThis("Hello") === "72olle"
encryptThis("good") === "103doo"
encryptThis("hello world") === "104olle 119drlo"
var encryptThis = function(text) {let answer = [];   function go(array){       let secondLetterValue = array[1];      array[0] = array[0].charCodeAt(0);      array[1] = array[array.length-1];      array[array.length-1] = secondLetterValue;      answer.push(array.join(‘’));   }text = text.split(‘ ‘);    text.forEach(function(word){      word = word.split(‘’);      go(word);    });return answer.join(‘ ‘);}
  • I make a variable that is an empty array called answer
  • I make text equal itself when it has the .split( ) method called on it with a space separating the elements in the new array to be made.
  • On the array that is now text, I call the .forEach( ) method on it with word as a placeholder argument representing each element in the text array when it goes through the for loop implied by the method .forEach( ).
  • Inside the code block, I make word equal itself with .split(‘’) being used on it so that it creates an array.
  • Then we call the function go with the word-array we made as an argument.
  • Earlier I made a function inside our function called go.
  • In our new function we make a new variable called secondLetterValue = array[1]. The second element in the array argument that we pass in.
let secondLetterValue = array[1];
  • I make the first character in the array argument equal itself converted into an ASCII code-character
array[0] = array[0].charCodeAt(0);
  • I make the second character in the array argument equal the last character in the array argument
array[1] = array[array.length-1];
  • I make the last character int he array argument equal secondLetterValue, the original value of what had been the 2nd element in the array at the start of this sub function.
  • Then I push into the array answer our array argument made into a string with .join(‘’), now that all the appropriate alterations have been done.
const encryptThis = text => text.split(‘ ‘).map(word => word .replace(/(^\w)(\w)(\w*)(\w$)/, `$1$4$3$2`) .replace(/^\w/, word.charCodeAt(0))) .join(‘ ‘);
  • Like me, they used .split( ) on the text argument. We separate elements based on whether there is a space between them as normal words do.
  • After this, they chain the .map( ) array function onto what is now an array and pass in the argument word to represent each element in the text array.
  • for each word element in the text array, we use the string method .replace( ),
  • as the first argument, we seek the
  • first character => (^\w)
  • second character => (\w)
  • third character => (\w*)
  • fourth character => (\w$)
  • as the second argument, we pass in
  • $1 — the first character is going to be (^\w)
  • $4 — the fourth character will be in the place of where the second one should be (\w$)
  • $3 — the third (\w*)
  • $2 — the second character (\w)
  • .replace( ) is called and we replace the first character [represetned by this RegEx expression] : /^\w/ with whatever the ASCII key for the character being referenced by the RegEx expression via the following string method word.charCodeAt(0).
  • You use 0 with the .charCodeAt( ) method to get an ASCII character returned to you.
  • Then we join it all together with .split( ).

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is a web developer, opera singer, actor, and lover of cats. (adrian-rosales.tech)

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Adrian Rosales

Adrian Rosales

is a web developer, opera singer, actor, and lover of cats. (adrian-rosales.tech)